what is the probability of ordinary year having 53 Mondays? explain with solution.
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2
An ordinary year has 365 days
A year has 52 weeks. Hence there will be 52 Sundays for sure.
52 weeks = 364 days
365 – 364 = 1 day
In an ordinary year, there will be 52 Sundays and 1 day will be left.
This one day can be, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.
Of these total 7 outcomes, the favourable outcome is 1.
Hence the probability of getting 53 Sundays = 1/7
A year has 52 weeks. Hence there will be 52 Sundays for sure.
52 weeks = 364 days
365 – 364 = 1 day
In an ordinary year, there will be 52 Sundays and 1 day will be left.
This one day can be, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.
Of these total 7 outcomes, the favourable outcome is 1.
Hence the probability of getting 53 Sundays = 1/7
pranavpatel2:
thanks
Answered by
1
no of days in a year is 365 days
53mondays+1 day
therefore sun,mon,tue,wed,Thu,Fri,sat
1/7
53mondays+1 day
therefore sun,mon,tue,wed,Thu,Fri,sat
1/7
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