Question

what is the probability of rhe event that a number chosen form 1 to 50 is an odd number option A(20) B(40) C(50) D(80) step by step
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Answer 1

Answer:

c) 50 %

Step-by-step explanation:

from 1 to 50 we have a total of 50 numbers, therefore we have a total of 50 possible picks. As every other number is odd, then 25 out of the 50 numbers are odd. Then the probability is the number of desireable picks (here it is odd numbers) over the number of possible picks.

Hence,

$\text{Probability} = \frac{25}{50}=\frac{1}{2} = 50$ %

Answer 2

The probability of the event that a number chosen form 1 to 50 is an odd number is 50%

Given :

A number chosen form 1 to 50

To find :

The probability of the event that a number chosen form 1 to 50 is an odd number is

(A) 20%

(B) 40 %

(C) 50%

(D) 80 %

Solution :

Step 1 of 3 :

Find total number of possible outcomes

Here it is given that a number chosen form 1 to 50

So total number of possible outcomes = 50

Step 2 of 3 :

Find total number of possible outcomes for the event

Let A be the event that the chosen number is an odd number

We know that there are 25 odd numbers from 1 to 50

So total number of possible outcomes for the event A is 25

Step 3 of 3 :

Find the probability

Hence the required probability

= P(A)

$\displaystyle \sf{ = \frac{Number \: of \: favourable \: cases \: to \: the \: event \: A }{Total \: number \: of \: possible \: outcomes }}$

$\displaystyle \sf{ = \frac{25}{50} }$

$\displaystyle \sf{ = \frac{50}{100} }$

= 50%

Hence the correct option is (C) 50%

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