What is the probability of sum equal to prime number on throwing two dice?
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On throwing two dices , ......
The minimum sum of two dices =2
The maximum sum =12
So total Number of incidents=2 to 12=11 sum incidents.
The favorable sums are 2,3,5,7,11
So Number of favorable incidents=5
So probability=no. of favorable incidents/total no. of incidents
= 5/11
The minimum sum of two dices =2
The maximum sum =12
So total Number of incidents=2 to 12=11 sum incidents.
The favorable sums are 2,3,5,7,11
So Number of favorable incidents=5
So probability=no. of favorable incidents/total no. of incidents
= 5/11
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