What is the probability of two digit numbers which are divisible by 5?
Answers
Answered by
3
Answer:
a = 10
d = 5
an = 95
n = ?
an = a + (n-1)d
95 = 10 + (n-1)5
85/5 = n-1
n-1 = 17
n = 18
Thus no. Of observations are 18.
Sp = [two digit no.s ]
E = two digit no.s divisible by 5
P(E) = 18/90
= 6/30
= 2/10
= 1/5
Ans...
Similar questions