what is the probability tha a leap year selected at random will contain 53 thursday ?
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A leap year has 366 days or 52 weeks and 2 odd days.
The two odd days can be:--
{Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday},{Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}.
So there are 7 possibilities out of which 2 have a Thursday. So the probability of 53 Thursday is 2/7.
Hope it helps !!
The two odd days can be:--
{Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday},{Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}.
So there are 7 possibilities out of which 2 have a Thursday. So the probability of 53 Thursday is 2/7.
Hope it helps !!
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