Question

what is the probability that 2 of the 10 packets tested would turn out to be defective?

Answer 1

n(A) = 2 ; n(S) = 10

p(A) = n(A)/n(S) = 2/10 (or) 1/5

#Hassan

Answer 2

So, there is a probability of 1/5 that 2 of the 10 packets tested would turn out to be defective.

We know, probability is the ratio of number of the number of favorable outcomes to the total number of possible outcomes. It measures the likelihood of the occurence of an event in the following way.

Probability = (Number of favorable outcomes) / (Total number of possible outcomes)

From the question, we get to know that, Total no. of possible outcomes = Total no. of packets to be tested = 10 and,

Number of favourable outcomes = No. of packets to be checked are defective = 2.

So, probability that the event of finding 2 defective packets out of 10 is given as :

Thus, Probability = (2/10) = 1/5.