What is the probability that a leap year selected at random will contain 53 Sundays?
Answers
Answered by
1
Answer:
1 by 7
Step-by-step explanation:
as there are 52 weeks and 2 days, it become 1by7
Answered by
0
Answer:
no.of days=366=364+2=52weeks+2days
probability that the remaining day contains a Sunday is 2/7
(MT, TW, WTh, ThF, FSa, SaS, SM)=7
(SaS, SM)=2
probability=2/7
for a non leap year it is 1/7
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