What is the probability that a leap year selected at random, will contain 53 sundays?
A) 1/7 B) 1/3 C) 2/7 D) 4/7
Answers
Answered by
1
Answer:
Option B is the correct answer...
Answered by
72
Correct option: (A)
A non-leap year has 365 days.
365 days = 52 weeks + 1 day
Since 52 weeks = 52 x 7 = 364 days
Hence there will be 52 Sundays in a year.
This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, or Sunday.
Out of these total 7 outcomes, the number of favourable outcomes is 1.
Hence, the probability of getting 53 Sundays = 1 / 7
Hope it's Helpful.....:)
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