what is the probability that a leap year selected at random will contain 53 Sunday
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2/7
is the answer.......
is the answer.......
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The probability of 53 Sundays will be find as follows:-
Any common year has 52 weeks and 1 day(52×7+1=365days)
But in a leap year it will be 52×7+2=366days
So firstly the probability of Sundays in the 52 weeks will be sure.
But probability of Sundays of last two days :-
Possibilities-(Sunday-Monday),(Monday-Tuesday),(Tuesday-Wednesday),(Wednesday-Thursday),(Thursday-Friday),(Friday-Saturday),(Saturday-Sunday).
So,Sundays are in two cases(Sunday-Monday),(Saturday-Sunday).
So,Probability of Sunday=2/7 Answer
Any common year has 52 weeks and 1 day(52×7+1=365days)
But in a leap year it will be 52×7+2=366days
So firstly the probability of Sundays in the 52 weeks will be sure.
But probability of Sundays of last two days :-
Possibilities-(Sunday-Monday),(Monday-Tuesday),(Tuesday-Wednesday),(Wednesday-Thursday),(Thursday-Friday),(Friday-Saturday),(Saturday-Sunday).
So,Sundays are in two cases(Sunday-Monday),(Saturday-Sunday).
So,Probability of Sunday=2/7 Answer
chhavi2629:
thank you so much
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