Question

what is the probability that a non leap year has 53 Sundays??

Answer 1

Answer:

1/7

Step-by-step explanation:

A non-leap year has 365 days => 52 weeks + 1 day.

This 1-day can be:

{Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday}

There are 7 possibilities out of which 1 possibility contain Sunday.

∴ Required probability = 1/7.

Hope it helps!

Answer 2

Step-by-step explanation:

A non-leap year has 365 days

A year has 52 weeks. Hence there will be 52 Sundays for sure.

52 weeks = 52 x 7 = 364 days .

365– 364 = 1day extra.

In a non-leap year there will be 52 Sundays and 1day will be left.

This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday,friday,Saturday, Sunday.

Of these total 7 outcomes, the favourable outcomes are 1.

Hence the probability of getting 53 sundays = 1 / 7.