Question

What is the Probability that an ordinary has 53 sundays? ​

Answer 1

So n(E) =1. Therefore the probability of a year having 53 Sundays = n(E)/n(S) = 1/7. If the year in question is a leap year, there are 366 days. Since 364 is a multiple of 7, there will be 52 Sundays, 52 Mondays,