Math, asked by Shaikh12azim, 2 months ago

What is the probability that an ordinary year has 53 sunday​

Answers

Answered by yashuharshuchinnu26
1

Answer: 1\7

Explanation: in 365 days number of weeks is equal to 52 weeks and 1 days mind one remaining there can be Sunday Monday Tuesday Wednesday Thursday Friday Saturday Sunday total of 7 outcomes the favourable outcomes is one probability of getting 53 cm equal to 1 / 7

Answered by josephvayalattu
0

Answer:

1/7

Step-by-step explanation:

see we have 365 days in a non-leap year.

52 weeks and one extra day= 365 days

52 weeks means definitely there are 52 sundays (this is true for all other days also).

that means if the extra day comes out to be sunday then we will have 53 sundays.

so now the ques boils down to what is the prob of this extra day to be a sunday .

this extra one day can be {monday or tuesday or wednesday or thursday or friday or saturday or sunday }= samplespace (s)

i.e n(s) = 7

so prob of this extra one day to be a sunday is 1/7.

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