what is the probability that an ordinary year has 53 sundays
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it's 1/7 and if it is a leap year then 2/7
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SOLUTION
The number of days in an ordinary year= 365.
The number of days in a week= 7
Therefore,
The number of complete weeks in a year= 365÷ 7
=) 52 days complete weeks in a year and 1 day is left as remainder.
Every week has 1 Sunday so there must be 52 Sunday in a year.
Now,
The remaining 1 day can be anyone of the 7 days.
Hence,
The probability for the remaining day of being Sunday
=) Number of possible outcomes/ number of total outcomes
=) 1/7
hope it helps ✔️
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