What is the probability that an ordinary year has 53 Sundays?
Answers
Given : An ordinary year
To Find : probability that an ordinary year has 53 Sundays
Solution:
Years are divided in2 categories
Leap year = 366 days
Non leap Year = 365 days ( also called Ordinary year)
365 Days = 52 * 7 + 1
Hence there are 52 complete weeks
so each day of week is 52 times
Now one left day can be any one of the 7 days of a week
Total Possible outcomes = 7
Favorable outcomes = 1 ( Sunday)
probability that an ordinary year has 53 Sundays = 1/7
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The probability that an ordinary year has 53 Sundays = 1/7.
An ordinary year has 365 days.
52 complete weeks and one day.
Possibilities for this one day are:
Total possibilities are 7.
[Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday]
Favorable cases = 1
Probability = 1/7
Thus, the probability that an ordinary year has 53 Sundays = 1/7
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