What is the probability that an ordinary year has 53 sundays?
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Question :-
What is the probability that an ordinary year has 53 sundays?
Required Answer :-
The ordinary year has 365 days i.e. 52 weeks and one day.
Now, sample space for the last (one) day:-
S = { Sunday, Monday, Tuesday,
Wednesday, Thursday, Friday,
Saturday }
n(S) = 7
Let A be the event of getting 53 sundays in a year.
A = { Sunday }
n(A) = 1
P(A) = n(A)/n(S)
P(A) = 1/7
Therefore, probability of getting 53 Sundays in a year is 1/7.
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Answer:
1/7
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