Math, asked by Anonymous, 3 months ago

What is the probability that an ordinary year has 53 sundays?

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Answers

Answered by Anonymous
4

Answer:

Question :-

What is the probability that an ordinary year has 53 sundays?

Required Answer :-

The ordinary year has 365 days i.e. 52 weeks and one day.

Now, sample space for the last (one) day:-

S = { Sunday, Monday, Tuesday,

Wednesday, Thursday, Friday,

Saturday }

n(S) = 7

Let A be the event of getting 53 sundays in a year.

A = { Sunday }

n(A) = 1

P(A) = n(A)/n(S)

P(A) = 1/7

Therefore, probability of getting 53 Sundays in a year is 1/7.

Hope it help you :)

Be brainly!!

Answered by dhanabalanhamsa
0

Answer:

1/7

Step-by-step explanation:

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