What is the probability that at least one marble is white if a bag has 3 green and 3 white marbles four marbles are selected at the same time?
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Hi there !
Here's the answer:
Bag contains
3 Green Balls
3 White Balls
Total Balls= 6
Let S be sample space
n(S) = no. of ways of selecting 4 marbles from 6 Balls= 6C4
= 6C2= (6×5)/2= 15
E be Event that selected ball contains at least one white ball.
( Atleast => min to max )
Possible cases:
1 white - 3C1= 3
2 white- 3C2= 6
3 white- 3C3= 1
The sum of these no. of cases is nothing but n(E)
n(E) = 3+6+1
Probability = n(E) / n(S)
= 10/15= 2/3
•°• Required probability = 2/3
:)
Hope it helps
Here's the answer:
Bag contains
3 Green Balls
3 White Balls
Total Balls= 6
Let S be sample space
n(S) = no. of ways of selecting 4 marbles from 6 Balls= 6C4
= 6C2= (6×5)/2= 15
E be Event that selected ball contains at least one white ball.
( Atleast => min to max )
Possible cases:
1 white - 3C1= 3
2 white- 3C2= 6
3 white- 3C3= 1
The sum of these no. of cases is nothing but n(E)
n(E) = 3+6+1
Probability = n(E) / n(S)
= 10/15= 2/3
•°• Required probability = 2/3
:)
Hope it helps
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