what is the probability that at least two persons out of a group of 3 persons were born in the same month??
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Topic Probability .
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Answers
Answered by
0
Let us assume that each month is equally likely as a birth month
There are
12
P
3
12P3 choices for the three distinct birthdays, taken in order.
And there are 12
3
123 choices for three birthdays altogether, taken in order.
P(all 3 different)=
12
3
12
P
3
=
1728
1320
=
72
55
P(at least 2 match)=1−
72
55
=
72
17
Hence, the answer is
72
17
.
Answered by
0
Step-by-step explanation:
Probability of at least two persons born in the same month = Number of possible outcomes/
Total outcomes
= 2/3
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