Biology, asked by sanjana041299, 5 months ago

What is the probability that III-13 express the disease?
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Answers

Answered by dishishukla98
4

Answer:

Since III-6 does not show the trait, only three possibilities remain (Aa, aA or AA). Thus, III-6 has a 2/3 chance of being Aa. III-13 is definitely a heterozygote.

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