what is the probability to get a different results by tossing two coins?
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Answer:
E6 = {HT, TH, HH} and, therefore, n(E6) = 3. Therefore, P(getting at least 1 head) = P(E6) = n(E6)/n(S) = ¾.
Step-by-step explanation:
There are four possible mutually exclusive outcomes on the toss of two coins as shown, each with a probability of 0.25. The sum of the probability of two of these outcomes (heads, tails or tails, heads) is 0.25 + 0.25 or 0.5. Probability applies to breeding horses as well as tossing coins.
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