what is the probablity that a letter pucked from the word examination is a constant
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1
Sample Space (S) = 11
Let 'A' be the event of getting a constant
n(A) = 5
p(A) = n(A) / n(s)
= 11 / 5
p(A) = 11 / 5
Let 'A' be the event of getting a constant
n(A) = 5
p(A) = n(A) / n(s)
= 11 / 5
p(A) = 11 / 5
Answered by
0
5/8 is the probability of picking a constant from the word examination.
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