Question

what is the procedure of pop sound experiment​

Answer 1

Answer:

• The pop sound experiment is done to find the presence of hydrogen gas.

Explanation:

• For conducting this experiment we would need test tubes, Magnesium ribbon, aqueous solution of diluted Hydrochloric acid, a matchstick, a plastic wrap to cover the test tube and a rubber band.

• For protection we would need lab glasses and also gloves because we have to be extra careful when handling the acid.

• For this at first we will take a test tube and we would pour the aqueous solution of diluted Hydrochloric acid in it.

• After this, we would add the magnesium ribbon in it.

• As soon as the magnesium ribbon touches the acid bubbles would be formed in the test tube.

• After that we would cover the test tune using the plastic wrap and rubber band.

• Then we would light a matchstick and would take the plastic wrap cover from the test tube. As soon as the burning matchstick is brought near the test tube a gas would be released and a pop sound would be heard.

• The following reaction takes place in the test tube.

Mg + HCl --------- > MgCl2 + H2.

• This H2 is the hydrogen gas released from the solution which is colourless and odourless gas.

• This pop sound experiment is used in identifying the hydrogen gas.

Answer 2

Answer:

The procedure of pop sound experiment is as follows :

i.) Take a dilute acid like hydrochloric acid (HCl) in a beaker.

ii.) Add some zinc granules in the beaker.

iii.) After sometime in the beaker we can see some bubbles emerging upwards in the beaker. These are the bubbles of hydrogen.

iv.) In order to test bubble bring a lighter, and the lighter burns with a pop sound because hydrogen is a flammable gas. Also the beaker becomes quite hot to touch because a considerable amount of heat is released in the reaction . Thus it is an exothermic reaction also.

Reaction :

We know that when a metal reacts with a dilute acid, the metal replaces hydrogen from its aqueous solution forming salt solution and hydrogen gas.

Metal + Acid(dil.) = Salt solution + Hydrogen gas

Here, zinc (Zn) metal reacts with dilute hydrochloric acid (HCl) , to form salt solution of zinc chloride (ZnCl) and hydrogen gas (H2).

2Zn(s) + 2HCl(aq) = 2ZnCl(aq) + H2(g)