Question

what is the product of (2y³-3y²+y+9) and (-y+3) and verify the result for y=1​

Answer 1

Step-by-step explanation:

(-y+3)×(2y^3-3y^2+y+9)

= -2y^4+3y^3-y^2+9y+6y^3-9y^2+3y+27

= -2y^4+9y^3-11y^2+13y+27

now,

put y=1

-2×1+9×1-11×1+13×1+27

= -2+9-11+13+27

=40