What is the product of polynomial 3xcube+5xsquare-7x-27
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Step-by-step explanation:
Given,
Let p, q and r are three zeroes of 3x^3 + 5x^2 - 7x - 27
p*q = 3.......(1)
We know,
Product of three zeroes of polynomial = - d/a
Then,
p*q*r = - (-27)/3 = 9......(2)
Put value of p*q from eq(1) in eq(2)
r = 9/3
r = 3
Therefore, third zero is 3
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