Question

what is the product of this algebraic question using identity (3/2x + 1)³= ?​

Answer 1

$\bigstar \bf \: answer \\ ( \frac{3}{2} x + 1) {}^{3} = ( \frac{3}{2} x) {}^{3} + (1) {}^{3} + 3 \times \frac{3}{2} x \times 1( \frac{3}{2} x + 1) \\ { \green{ \mathbb{ using \: the \: identity \: (a + b) {}^{3} = a {}^{3} + b {}^{3} + 3ab(a + b)}}} \\ = \frac{27}{8} {x}^{3} + 1 + \frac{9}{2} x( \frac{3}{2} x + 1) \\ = \frac{27x {}^{3} }{8} + 1 + \frac{27x {}^{2} }{4} + \frac{ 9x}{2}$