Question

What is the radius of a circle whose equation is (x + 5)2 + (y – 3)2 = 42? 2 units 4 units 8 units 16 units

Answer 1

Answer:

see answer in above pic

thank me

follow me

marked me as brainlist answer first ok

vote me verified me ok

Answer 2

Correct question:

What is the radius of a circle whose equation is (x + 5)² + (y – 3)² = 4²?

a) 2 units

b) 4 units

c) 8 units

d) 16 units

Answer:

The correct answer is option b) 4 units.

Given:

A circle is defined by the equation (x + 5)² + (y – 3)² = 4².

Find:

The radius of the circle.

Solution:

The standard equation for a circle is as follows -

(x - h)² + (y - k)² = r²

where h and k are the coordinates of the centre of the circle defined by the equation.

Center = (h,k)

r is the radius of the circle defined by the equation.

The given equation is (x + 5)² + (y – 3)² = 4².

Comparing the given equation with the standard equation, we get

h = -5

k = 3

r = 4

∴ Coordinates of the center of the circle = (-5, 3)

Radius of teh circle = r = 4 units.

Hence, the radius of the circle whose equation is (x + 5)² + (y – 3)² = 4² is 4 units.

So, option b) is the correct answer.

#SPJ2