Question

What is the radius of a solid sphere rotating about its diameter if its radius of gyration is 3.162

Answer 1

Answer:

Angular momentum will remain the same since external torque is zero.

Angular momentum will remain the same since external torque is zero.MI will increase since r increases (I=

Angular momentum will remain the same since external torque is zero.MI will increase since r increases (I= 5

Angular momentum will remain the same since external torque is zero.MI will increase since r increases (I= 52

Angular momentum will remain the same since external torque is zero.MI will increase since r increases (I= 52

Angular momentum will remain the same since external torque is zero.MI will increase since r increases (I= 52 mr

Angular momentum will remain the same since external torque is zero.MI will increase since r increases (I= 52 mr 2

Angular momentum will remain the same since external torque is zero.MI will increase since r increases (I= 52 mr 2 )

Angular momentum will remain the same since external torque is zero.MI will increase since r increases (I= 52 mr 2 )Angular velocity decreases since L=Iω is conserved.

Angular momentum will remain the same since external torque is zero.MI will increase since r increases (I= 52 mr 2 )Angular velocity decreases since L=Iω is conserved. Rotational KE: K

Angular momentum will remain the same since external torque is zero.MI will increase since r increases (I= 52 mr 2 )Angular velocity decreases since L=Iω is conserved. Rotational KE: K rot

Angular momentum will remain the same since external torque is zero.MI will increase since r increases (I= 52 mr 2 )Angular velocity decreases since L=Iω is conserved. Rotational KE: K rot

Angular momentum will remain the same since external torque is zero.MI will increase since r increases (I= 52 mr 2 )Angular velocity decreases since L=Iω is conserved. Rotational KE: K rot =

Angular momentum will remain the same since external torque is zero.MI will increase since r increases (I= 52 mr 2 )Angular velocity decreases since L=Iω is conserved. Rotational KE: K rot = 2I

Angular momentum will remain the same since external torque is zero.MI will increase since r increases (I= 52 mr 2 )Angular velocity decreases since L=Iω is conserved. Rotational KE: K rot = 2IL

Angular momentum will remain the same since external torque is zero.MI will increase since r increases (I= 52 mr 2 )Angular velocity decreases since L=Iω is conserved. Rotational KE: K rot = 2IL 2

Angular momentum will remain the same since external torque is zero.MI will increase since r increases (I= 52 mr 2 )Angular velocity decreases since L=Iω is conserved. Rotational KE: K rot = 2IL 2

Angular momentum will remain the same since external torque is zero.MI will increase since r increases (I= 52 mr 2 )Angular velocity decreases since L=Iω is conserved. Rotational KE: K rot = 2IL 2

Angular momentum will remain the same since external torque is zero.MI will increase since r increases (I= 52 mr 2 )Angular velocity decreases since L=Iω is conserved. Rotational KE: K rot = 2IL 2 decreases since I increases.

Explanation:

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