Question

What is the radius of the resultant circle, if its diameter is decreased by half

Answer 1

Answer:

The radius will also be decreased by half.

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Area of the circle is proportional to square of its radius (A = pi * r^2).

Let the initial radius is (r1), the initial area will be

A1 = pi * (r1) ^ 2.

Now radius is decreased by 50%.

The new radius will be (r1) - { 50% of (r1 )}

New radius = (r1) - 50*(r1)/100 = (r1) - (r1)/2= (r1)/2.

New area = pi * {(r1)/2} ^ 2} = {pi * (r1)^2} / 4 = A1 / 4.

The new area will be 1/4 th of the original area.

Decrease in area in percentage =

{(Original area - New area)/ (Original area)} * 100

= {(A1 - A1/4)/A1} * 100 = 75.

Area will be decreased by 75%