Question

What is the radius of this semicircle? Since diameter is a + b, radius is ż (a + b). (a + b) Vab a b​

Answer 1

Suppose at t=0,y=0andt=t,y=y
t
=
0
,
y
=
0
and
t
=
t
,
y
=
y

(a) Total magnetic flux=B→.A→
B
→
.
A
→

where A→=a2(kˆ)andB→=B0ya(kˆ)
A
→
=
a
2
(
k
^
)
and
B
→
=
B
0
y
a
(
k
^
)

∴(ϕ)=B0ya.(a2)=B0ya
∴
(
ϕ
)
=
B
0
y
a
.
(
a
2
)
=
B
0
y
a

Net emf. e=−dϕdt=−b0adydt=−B0adydt=−B0av(t)
e
=
-
d
ϕ
d
t
=
-
b
0
a
d
y
d
t
=
-
B
0
a
d
y
d
t
=
-
B
0
a
v
(
t
)

As total resistance =R
∴|i|=|e|R=B0av(t)R
∴
|
i
|
=
|
e
|
R
=
B
0
a
v
(
t
)
R