Question

What is the
range of the
function
f(x)=x^2-x-6

​

Answer 1

The given function is an upward open parabola. Its maximum value will be infinity when x tends towards ±∞. To find the minimum value, differentiate it w.r.t. x.

y=x2−x−6

=> dydx=2x−1

For extremum, dydx=0

=> 2x−1=0=>x=12

f(12)=0.52−0.5−6=−6.25

∴, Range ∈(−6.25,∞)

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Answer 2

Answer:

-6. 25

Step-by-step explanation:

y=x²-x-6

=> dy/dx= 2x-1

for extremum, dy/dx=0

=> 2x-1=0 =>x=1/2

f(1/2) = 0.5²-0.5-6

-6.25

Range is 6.25

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