Question

What is the range of the function y=2x2-8x-3

Answer 1

Answer:

To do this, use

-b/2a

to give you the line of symmetry. So

− 8/2*2 = -2

2

Now, you can plug this back into the original so you will receive

y =2 (-2)^2 +8 (-2) -3

This comes out to a value of

y = 8 - 16 - 3

y= -11

So the vertex will be  

( -2, - 11).

graph{2x^2 + 8x -3 [-5, 5, -15, 5]}