Math, asked by dfcv, 1 year ago

What is the range of the real valued function f(x) = 1/√x^2-1

Answers

Answered by abhi178
2
f (x) =1/root(x^2-1)

root (x^2-1)> 0
also, 1/root (x^2-1)> 0 except {+_1}

hence f (x)> 0 except x=+_1
so, Range €(0, infinite)-{+1,-1}
where e means belongs to
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