Question

What is the rate of change between the interval of x = pi over 4 and x = pi over two ?

Answer 1

$\bold{Answer :}$

Let us consider a function y = f(x)

Then, dy/dx = f'(x)

This f'(x) is the rate of change.

Thus, in the given interval, the rate of change

= f'(π/2) - f'(π/4)

#$\bold{MarkAsBrainliest}$

Answer 2

Answer:

$R= \frac {-16} {π}$

Rate of change between the interval x = a and x = b:

$R= \frac {[f (b)- f (a)]} {(b- a)}$

In this problem, the given data are,

a= π, b= 3π/2

$R= \frac {[f(3\pi/2)- f(\pi)]} {\frac {3\pi} {(2- \pi)}}$

According to the graph:

$f(3\pi/2)= -1$

$f(\pi)= 7$

Substituting in the above formula we get

$R= \frac {(-1-7)} {[(3\pi-2\pi)/2]}$

$R= \frac {(-8)} {(\pi/2)}$

$R= \frac {(-8)} {(2/\pi)}$

$R= \frac {-16} {\pi}$