Question

What is the rate of change for the interval between 0 and 2 for the quadratic equation as f(x) = 2x2 + x – 3 represented in the table?

Answer 1

Step-by-step explanation:

By definition the rate of change of a function is given by:

AVR = \frac{f(x2) - f(x1)}{x2 - x1}AVR=

x2−x1

f(x2)−f(x1)

For the interval [0, 2] We have to make use of the table:

f(0)=-3 f(2)=7f(0)=−3f(2)=7

Therefore, substituting values in the given expression we have that the average change of rate is given by:

AVR = \frac{7-(-3)}{2-0}AVR=

2−0

7−(−3)

Rewriting we have:

AVR = \frac{7+3}{2-0}AVR=

2−0

7+3

AVR = \frac{10}{2}AVR=

2

10

AVR = 5AVR=5

Answer: