Math, asked by idkidkidk026, 8 months ago

What is the rate of interest which yields an interest of ₹560 on a sum of ₹28000 after 2 years?​

Answers

Answered by aviralkachhal007
14

\huge\star\underline{\mathtt\red{A}\mathtt\green{N}\mathtt\blue{S}\mathtt\purple{W}\mathtt\orange{E}\mathtt\pink{R}}\star\:

According to the question.

t = 2 years

p = 28000

interest = 560

560 = 28000xRx2/100

560x100 = 56000xR

56000/56000 = R

R = 1

Rate is 1 %

Answered by DivineEyes
38

{\fbox{\fbox{\fbox{\fbox{\fbox{\huge\sf\purple{AnsWeR}}}}}}}

  • \large \sf{ According\:to\: question}

t = 2 years

p = 28000

interest = 560

\sf{560 = 28000xRx2/100}

\sf{560x100 = 56000xR}

\sf{\frac{56000}{56000 }= R}

R = 1

Rate is 1 %.

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