Question

what is the rate of %
$410 = 4000(1 + \frac{r}{100} ) {}^{2}$
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Answer 1

Answer:

what is the rate of %

From the given expression

i.e to find the value of r from given expression

Step-by-step explanation:

$410=4000(1+\frac{r}{100} )^{2} \\\frac{41}{400} =(1+\frac{r}{100} )^{2} \\(1+\frac{r}{100} )=\frac{\sqrt{41} }{20} \\r=(\frac{\sqrt{41} }{20}-1)*100$

Hence r will be negative that means your question is wrong

i mean 410  is amount which can not be less than principal.

Please check your question.