what is the ratio between the sum of the interior angles of a regular Pentagon and a regular decagon.
pls show the working pls
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Sum of interior angles of a polygon = (n-2)180
Sum of interior angles of a pentagon = (5-2)180 = 3×180 = 540°
Sum of interior angles of a decagon = (10-2)180 = 8×180 = 1440°
Ratio = 540:1440
27:72
3:8
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