what is the ratio of areas of 2 similar triangles whose sides are in the ratio 3:4...
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▶ Question;-
Sides of two triangles are in the ratio 3:4 find the ratio of their areas?
▶ Method of Solution;
➡ Note;- We know that The ratio of the areas of two similar triangles is equal to the Ratio of the square of Corresponding Side's.
Now,. ➡ Let to be Small side of Triangle∆ABC in which AB measure 3.
Also ,
→ Now, Let to be larger side of Triangle∆DEF in which DE measure 4
Using theorem,
→ ar(ABC)/ar(DEF) = AB²/DE²
→ ar(ABC)/ar(DEF) = (3)²/(4)²
→ ar(ABC)/ar(DEF) = 9/16
Hence,
→Sides of two triangles are in the ratio 3:4 find the ratio of their areas is 9:16
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▶ Question;-
Sides of two triangles are in the ratio 3:4 find the ratio of their areas?
▶ Method of Solution;
➡ Note;- We know that The ratio of the areas of two similar triangles is equal to the Ratio of the square of Corresponding Side's.
Now,. ➡ Let to be Small side of Triangle∆ABC in which AB measure 3.
Also ,
→ Now, Let to be larger side of Triangle∆DEF in which DE measure 4
Using theorem,
→ ar(ABC)/ar(DEF) = AB²/DE²
→ ar(ABC)/ar(DEF) = (3)²/(4)²
→ ar(ABC)/ar(DEF) = 9/16
Hence,
→Sides of two triangles are in the ratio 3:4 find the ratio of their areas is 9:16
✍✍✍✍✍✍✍✍✍✍✍✍✍
Read more on Brainly.in ⬇⬇
Answered by
8
Given:-
Side of Ratio = 3:4
We know that The ratio of the areas of two similar triangles is equal to the Ratio of the square of Corresponding Sides.
•°• Area will be 3²:4²
= 9:16
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