Question

What is the ratio of distance travel in 4 th second and 10 th second if object starts from rest.

Answer 1

Answer:

7:19

Explanation:

Here, we use the following formula, Sn= u+a/2(2n-1). Now, S4=0+10/2(2*4-1)= S4=70/2. And, S10=0+10/2(2*10-1)=190/2. (we have time=n=4 and 10 respectively). Thus, ratio of 4th and 10th second =70/2*2/190=7:19.