Question

what is the ratio of molecules in 1 mole of NH3 and 1mole of HNO3. solve the problem ​

Answer 1

The ratio of molecules in 1 mole of $NH_3$ and 1 mole of $HNO_3$ is 1:1.

Explanation:

• To identify the ratio, the number of molecules present in 1 mole of $NH_3$ and $HNO_3$ must be calculated.
• To calculate it, the following calculation must be done:

Given:

Number of moles of $NH_3$ = 1

Number of moles of $HNO_3$ = 1

To find:

Ratio of molecules in 1 mole of $NH_3$ and 1 mole of $HNO_3$ = ?

Formula to be used:

• Number of molecules = Number of moles × Avogadro number
• Ratio = $\frac{Numebr of molecules in NH_3}{Number of molecules in HNO_3}$

Calculation:

No. of molecules in $NH_3$

No. of molecules in $NH_3$ = Number of moles × Avogadro number

No. of molecules in $NH_3$ = 1 × $6.022\times10^{23}$

No. of molecules in $NH_3$ = $6.022\times10^{23}$.

No. of molecules in $HNO_3$

No. of molecules in $HNO_3$ = Number of moles × Avogadro number

No. of molecules in  $HNO_3$  = 1 × $6.022\times10^{23}$

No. of molecules in  $HNO_3$   = $6.022\times10^{23}$

Ratio of molecules

Ratio = $\frac{Numebr of molecules in NH_3}{Number of molecules in HNO_3}$

$Ratio = \frac{6.022\times10^{23}}{6.022\times10^{23}}$

Ratio = 1:1

Conclusion:

Thus the ratio of molecules in 1 mole of $NH_3$ and 1 mole of $HNO_3$ is calculated as 1:1.

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