Question

What is the ratio of number of tamper unit cell in the BBC and fcc

Answer 1

Explanation:

In a FCC lattice there rer 8 atoms at eight corners and 6 at face centers,

Now each corner contributes to eight cells so per unit cell contribution is 1/8×8=1 atom.

Now similarly each face center contributes to two unit cells so contribution per unit cell by six face centers is equal to 1/2×6=3 atoms. Hence total no. of atoms per unit cell of FCC lattice is (1+3)=4 atoms.

For BCC-

A bcc has one atom in center and 1/8 th part of 8 corner atoms i.e 1 atom.

In total there are 1+1=2 atoms.

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