Question

what. is the ratio of strength of electric field at a point on axial line and a point on same distance a equitorial line of an electric dipole of very small length​

Answer 1

The ratio of strength of electric field at a point on axial line and a point on same distance a equatorial line of an electric dipole is 2 : 1 .

• At axial line , electric field = ( 1 / 4 * π * ε₀) * 2 * P / r^3
• At equatorial line , electric field =  ( 1 / 4 * π * ε₀) * P / r^3
• Ratio = ( Field at axial line ) / ( Field at equatorial line )

                 = (  ( 1 / 4 * π * ε₀) * 2 * P / r^3 ) / ( ( 1 / 4 * π * ε₀) * P / r^3 )

                 =  2 : 1

Answer 2

The ratio of strength of electric field at a point on axial line and point on same distance equitorial line of an electric dipole is 2 : 1 due to the following reasons:

- A point charge with the charge of magnitude Q, at a point of distance r away from the point charges produces the magnitude of electric field E.

- The formula is given by equation,

E = 1 × 2P /4 πε0 r^3

- The positive and negative charge of the electric dipole through which line passes is the axial line of the dipole.

- the electric field at the axial line is equal to,

E(axial) = 1 × 2P /4 πε0 r^3...(i)

- the electric field at equatorial line is equal to,

E(equatorial)= 1 × P /4 πε0 r^3...(ii)

- Therefore, the ratio of the electric field intensity at the point on the equatorial line to the electric field at the point on axial line is,

By dividing (i) equation with (ii) equation we have,

- E(axial)/E(equatorial) =

1 × 2P /4 πε0 r^3/ 1 × P /4 πε0r^3

= 2/1

- *E(axial) : E(equatorial) = 2:1*