Question

What is the ratio of the average molecular kinetic energy of UF6 to that of H2 both at 300K?

Answer 1

The average kinetic energy can be shown as:

KA = (3 /2) nRT

Where T is temperature of substance

n is number of moles

R is gas constant

KA1 /KA2 = T1 /T2

T1 =T2 = 300 K

KA1 /KA2 = 300 /300 = 1 :1

The ratio of the average molecular kinetic energy of UF6 to that of H2 is 1:1

Answer 2

Answer:

1:1

Explanation:

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