Math, asked by Soniya2005, 1 year ago

What is the ratio of the interior angle of a pentagon and a decagon.

Answers

Answered by TooFree
21

Pentagon = 5 sided polygon

Decagon = 10 sided polygon

.

 \boxed {\text{Interior angle = }\dfrac{(n-2) \times 180 }{n} }

.

Find the interior angle of a pentagon:

 \text{Interior angle of a pentagon = }\dfrac{(5-2) \times 180 }{5} } = 108 \textdegree

.

Find the interior angle of a decagon:

 \text{Interior angle of a decagon = }\dfrac{(10-2) \times 180 }{10} } = 144 \textdegree

.

Ratio of the angles:

Pentagon : Decagon = 108 : 144 = 3 :4

.

Answer: The ratio is 3:4

Answered by Anonymous
23

Answer:

To Find:-

Ratio of the interior angle of a Pentagon and a Decagon.

We know,

Interior Angle of a polygon of side n:-

\boxed{\large\tt\blue{\frac {(n-2) \times {180}^{\circ}}{n}}}

Therefore,

Interior angle of a Pentagon:-

Sides of a Pentagon = 5

Hence as per the formula, expression will be:-

\tt{\frac {(5-2) \times {180}^{\circ}}{5}}

(Expression as per the formula given above)

\tt{= \frac {3 \times {180}^{\circ}}{5}}

(In this step, we have Subtracted 2 from 5 and the result is 3. This change can be seen in the nominator)

\tt{= \frac {3 \times {\cancel {{180}^{\circ}}}}{{\cancel {5}}}}

(In this step, we have cancelled 180° with 5 taking common 5)

\tt{= \frac {3 \times {36}^{\circ}}{1}}

(Result after Dividing them)

\tt\purple{= {108}^{\circ}}

(After Multiplication/Answer)

Therefore, interior angle of a Pentagon is 108°.

NOW,

Interior angle of a Decagon:-

Sides of a Decagon = 10

Hence as per the formula, expression will be:-

\tt{\frac {(10-2) \times {180}^{\circ}}{10}}

(Expression as per the formula given above)

\tt{= \frac {8 \times {180}^{\circ}}{10}}

(In this step, we have Subtracted 2 from 10 and the result is 8, this change can be seen in the nominator)

\tt{= \frac {8 \times {\cancel {{180}^{\circ}}}}{{\cancel {10}}}}

(In this step, we have cancelled 180° with 10 taking common 10)

\tt{= \frac {8 \times {18}^{\circ}}{1}}

(Result after Dividing them)

\tt\purple{= {144}^{\circ}}

(After Multiplication/Answer)

_____________...

Hence, ratio between their angles:-

\tt{Pentagon:Decagon}

(Written in this way so that we can get the suitable answer)

\tt{= \frac {Pentagon}{Decagon}}

(As we know, numbers in ratio (:) form equals to division (÷) form)

\tt{= \frac {{108}^{\circ}}{{144}^{\circ}}}

(Putting their values to their respective places)

\tt{= \frac {{\cancel {{108}^{\circ}}}}{{\cancel {{144}^{\circ}}}}}

(Cancelled)

\tt{= \frac {3}{4}}

(Simplest form)

\boxed{\huge\tt\green{=3:4}}

\boxed{\rm{(ANSWER)/Ratio}}

_______...

REQUIRED ANSWER:-

\tt{\therefore} Ratio of interior angles of a Pentagon and a Decagon is \boxed{\large\tt\orange{3:4}}.

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