What is the ratio of the number of atoms of elements potassium, chlorine and oxygen respectively present in 245 g of KCIO,? 1) 2:2:2 2) 1:1:3 3) 39 : 36:48 4) 1:2:6 chloring in
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Explanation:
KClO
3
⟶ molecular weight = 122.5gmol
−1
There is 1 mole of potassium in 1 mole of KClO
3
=1×39=39g
There is 1 mole of Cl=1×35.5=35.5g
and 3 mole of oxygen =3×16=48g
Moles of KClO
3
=
molecularweight
Givenweight
=
122.5gmol
−1
245g
Moles of KClO
3
=2
∴ Moles of Potassium =2
Moles of Chlorine =2
Moles of Oxygen =6
(1) Number of atoms of K = Moles × Avogadro's number
=2×6.022×10
23
=12.044×10
23
(2) Number of atoms of Cl = 2×6.022×10
23
=12.044×10
23
(3) Number of atoms of Oxygen = 6×6.022×10
23
=36.132×10
23
Ratio of number of atoms of K,Cl & O=1:1:3 .
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