Question

what is the ratio of the number of molecules in 71 gram of chlorine to the number of molecules in 2 gram of hydrogen

Answer 1

Molar mass = Atomic mass in grams
Therefore, for chlorine
Atomic mass = 35.5 u
Therefore, molar mass = 35.5 g
No. Of moles in 71 g = 71/35.5= 2
No. Of particles in 2 moles = 2*avogadros constant

Similarly, for hydrogen
Atomic mass = 1 and molar mass = 1
There fore, there are two moles in 2 g
No. Of particles= 2* Avogadros constant

Ratio= 2*avogadros constant/2*avogadros constant = 1

Answer 2

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