What is the ratio of the time of free fall and the time for quarter oscillation of a pendulum whose length is equal to the particular height of free fall?Will it be the same even on moon?
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Explanation:
The period of a simple pendulum is T=2π√Lg T = 2 π L g , where L is the length of the string and g is the acceleration due to gravity.The pendulum have maximum and minimum acceleration where the velocity is a maximum. At the elevated point of its motion, kinetic energy is least (i.e. zero) and potential energy is greatest. The acceleration is a maximum at the endpoints of the pendulum, and a least (zero) in the center, at the lowest point.
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