Question

what is the ratio of the velocity of ch4 and o2 molecules so that they are associate with de broglie waves of equal wavelength?

Answer 1

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Answer 2

Answer: The ratio of the velocity of $CH_4\&O_2$ molecules is 2:1.

Explanation:

let the mass velocity of methane and oxygen molecule be $v_1$ and$v_2$

$m_1,m_2$ = masses of methane and oxygen gas molecule

$m_1=16g/mol, m_2=32g/mol$

$\lambda _1,\lambda _2$ = wavelength of methane and oxygen gas molecules respectively

de Broglie equation of wavelength: $\lambda =\frac{h}{mv}$

$\lambda _1=\lambda _2(given)$

$\frac{h}{16g/mol\times v_1}=\frac{h}{32g/mol\times v_2}$

$\frac{v_1}{v_2}=\frac{2}{1}$

The ratio of the velocity of $CH_4\&O_2$ molecules is 2:1.