Math, asked by tramachandrappa, 1 year ago

What is the real solution set for|
x^2-3x-4|=9-|x^2-1|?

Answers

Answered by Krisha1574

0

Answer:

x= -4

Step-by-step explanation:

x^2 - 3x - 4 = 9 - x^2 - 1

-3x - 4 = 9 - 1

-3x = 8 + 4

-3x = 12

x = -4

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