Question

What is the reciprocal of a²
1) a
2) 1/a-²
3) a-²

(With steps please !)

Answer 1

We know that equation ax²+bx+c=0

Then sum of roots = a−b and product of roots= ac

Let the other zero be α

Therefore, the other zero is α¹

Now, α× α¹= a ²−96a

=>1= a² −96a

=>a ²2+9−6a=0

=>a ²−6a+9=0

=>a²−3a−3a+9=0

=>a(a−3)−3(a−3)=0

=>(a−3)(a−3)=0

=>a=3 and a=3