Question

What is the reduction potential of zinc electrode in 0.01m znso4 solution?

Answer 1

Answer:

Concentration of ZnSO4 solution =0.1M

% of dissociation of ZnSO4 solution =95%

Concentration of Zn+2 ions in ZnSO4 solution =0.1×95100

⇒0.095M

Thus,the electrode can be represented as Zn(s)/Zn+2(0.095M)

Reduction reaction taking place at this electrode is

Zn+2+2e−→Zn(s)(Here n=2)

According to Nernst equation,the reduction potential of above electrode is given by

EZn+2/Zn=E0Zn+2/Zn−0.059nlog10.095

EZn+2/Zn=−0.76+0.0592log0.095

EZn+2/Zn=-0.79Volt